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least squares solver for MxN matrices using QR householder algorithm
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@@ -17,6 +17,7 @@ set(tests
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helper
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hatvee
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copyto
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least_squares
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)
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add_custom_target(test_build)
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@@ -0,0 +1,69 @@
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#include "test_macros.hpp"
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#include <matrix/math.hpp>
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using namespace matrix;
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int test_4x3(void);
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int test_4x4(void);
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int main()
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{
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int ret;
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ret = test_4x4();
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if (ret != 0) return ret;
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ret = test_4x3();
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if (ret != 0) return ret;
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return 0;
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}
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int test_4x3() {
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// Start with an (m x n) A matrix
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float data[12] = {20.f , -10.f , -13.f ,
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17.f , 16.f , -18.f ,
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0.7f, -0.8f, 0.9f,
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-1.f , -1.1f, -1.2f};
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Matrix<float, 4, 3> A(data);
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float b_data[4] = {2.0, 3.0, 4.0, 5.0};
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Vector<float, 4> b(b_data);
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float x_check_data[3] = {-0.69168233f,
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-0.26227593f,
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-1.03767522f};
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Vector<float, 3> x_check(x_check_data);
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LeastSquaresSolver<float, 4, 3> qrd = LeastSquaresSolver<float, 4, 3>(A);
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Vector<float, 3> x = qrd.solve(b);
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TEST(isEqual(x, x_check));
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return 0;
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}
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int test_4x4() {
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// Start with an (m x n) A matrix
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float data[16] = { 20.f , -10.f , -13.f , 21.f ,
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17.f , 16.f , -18.f , -14.f ,
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0.7f, -0.8f, 0.9f, -0.5f,
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-1.f , -1.1f, -1.2f, -1.3f};
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Matrix<float, 4, 4> A(data);
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float b_data[4] = {2.0, 3.0, 4.0, 5.0};
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Vector<float, 4> b(b_data);
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float x_check_data[4] = { 0.97893433f,
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-2.80798701f,
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-0.03175765f,
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-2.19387649f};
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Vector<float, 4> x_check(x_check_data);
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LeastSquaresSolver<float, 4, 4> qrd = LeastSquaresSolver<float, 4, 4>(A);
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Vector<float, 4> x = qrd.solve(b);
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TEST(isEqual(x, x_check));
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return 0;
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}
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/* vim: set et fenc=utf-8 ff=unix sts=0 sw=4 ts=4 : */
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@@ -124,4 +124,26 @@ for i in range(1,3):
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A_pow = A_pow.dot(A)
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print(eA_approx)
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print('\nqr decomposition 4x4')
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A = array([[20.0, -10.0, -13.0, 21.0], [ 17.0, 16.0, -18.0, -14], [0.7, -0.8, 0.9, -0.5], [-1.0, -1.1, -1.2, -1.3]])
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b = array([[2.], [3.], [4.], [5.]])
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x = scipy.linalg.lstsq(A,b)[0]
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print('A:')
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pprint(A)
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print('b:')
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pprint(b)
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print('x:')
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pprint(scipy.linalg.lstsq(A,b)[0])
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print('\nqr decomposition 4x3')
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A = array([[20.0, -10.0, -13.0], [ 17.0, 16.0, -18.0], [0.7, -0.8, 0.9], [-1.0, -1.1, -1.2]])
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b = array([[2.], [3.], [4.], [5.]])
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x = scipy.linalg.lstsq(A,b)[0]
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print('A:')
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pprint(A)
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print('b:')
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pprint(b)
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print('x:')
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pprint(x)
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# vim: set et ft=python fenc=utf-8 ff=unix sts=4 sw=4 ts=8 :
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